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How do you find the measure of the sides of a rhombus by its diagonals?
The diagonals of a rhombus bisect one another at right angles. So you can use Pythagoras on half the lengths of the diagonals. If the two diagonals ore of lengths a and b, then side2 = (a/2)2 + (b/2)2 or, equivalently, side = 1/2*sqrt(a2 + b2)
How do you find the sides of a rhombus if diagagonal are given?
The diagonals bisect each other at right angles. So you could use Pythagoras on half the diagonals. So, if the diagonals are a and b units long, then half the diagonals are a/2 and b/2 units long. Then, by Pythagoras, the sides of the rhombus are sqrt[(a/2)2 + (b/2)2]
What 2d shape has 4 sides 2 acute angles 2 obtuse angles diagonals intersect at right angles and 2 pairs of adjacent sides equal in lenght?
A kite.
What are facts about parallelogram?
Opposite sides are congruent Opposite sides are parallel Opposite angles are equal Consecutive angles are supplementary Diagonals bisect each other Diagonals form 2 equal triangles
What are the 2 charcteristic's of the rhombus?
There are many characteristics of a rhombus. Every rhombus is a parallelogram, so it has all the characteristics of one: opposite sides are parallel, adjacent angles are supplementary, and the diagonals bisect each other. Additionally, there are two other characteristics that apply to rhombuses: the opposite angles are congruent and the diagonals are perpendicular.
