Yes.
5, 10, and 20 are all multiples of 5 and factors of 20.
Not AllTo find out if all numbers that have 5 as a factor have 2 as a factor, you can list the multiples of each. 5's multiples are 5, 10, 15, 20...2's multiples are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20...5 and 15 are multiples of 5, but not 2, so all numbers that have 5 as a factor DO NOT have 2 as a factor.It is not really necessary to write that all out because the fact that 5 is an odd number and 2 is only a factor of even numbers indicates that all numbers that have 5 as a factor would not have 2 as a factor. Only the multiples of 5 that are even have 2 as a factor also.
Since 10 is a multiple of 5, all multiples of 10 are multiples of 5.
Any number is a factor and a multiple of itself. Other factors are less than the number, other multiples are more. 5 is a factor of 10. 10 is a multiple of 5.
No, 5 is a factor of 10 and 20. 10 and 20 are multiples of 5.
Because they are multiples of 5. All multiples of 5 have 5 as a factor, which means they are divisible by 5.
Since 10 is a factor of 20, all multiples of 20 are multiples of 10. This is also true of 1, 2, 4 and 5.
False, all multiples of 10 end in 0. All multiples of 5 end in 5 or 0.
All of them are.
Factors of 10: 1, 10, 2, 5 Multiples of 5: 5, 10, 15, etc. From this, we see that 5 and 10 are factors of 10 and multiples of 5. Therefore, there are two numbers that are factors of 10 but not 5. They are: 1 and 2
There are infinitely many multiples of 10 so it is far from clear what you mean by "all 5" multiples. Any integer which ends in a 0 is a multiple of 10.
Listen up, honey. If a number has 10 as a factor, that means it can be divided evenly by 10. And guess what? Any number that can be divided by 10 can also be divided by 5 because 10 is just 5 times 2. So, yes, any number that has 10 as a factor will also have 5 as a factor. Case closed.