5, 10, and 20 are all multiples of 5 and factors of 20.
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There are infinetly many numbers which have 2 and 5 as their factors. Some examples are 10, 20, 30, 40, etc. 2 and 5 both are prime numbers and their common multiples are the multiples of 2 x 5 = 10. So all the multiples of 10 have 2 and 5 as their factors. However if consider 2 and 5 as the only two proper factors, then the required number is 10.
No. A factor is a number or algebraic expression by which another is exactly divisible. A multiple is a number that can be divided by another number without a remainder. Factors go into numbers, numbers go into multiples.
To find how many three-digit numbers are multiples of 20, we need to determine the range of three-digit numbers divisible by 20. The smallest three-digit number divisible by 20 is 100, and the largest is 980. To find the count of numbers in this range, we can divide the largest number by 20 and subtract the result of dividing the smallest number by 20, then add 1 to account for the inclusive range. Therefore, the number of three-digit multiples of 20 is (980/20) - (100/20) + 1 = 49 - 5 + 1 = 45.
They are all multiples of 2. If you're asking for factors: 1, 2 and 4.
It depends on what they are compared to. In general, factors will be smaller than the number they are compared to, and multiples will be larger. Overall, factors tend to be smaller than multiples, but 20 is a factor of 40 and 10 is a multiple of 5, so there are exceptions.