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Yes it does, because of its 2 ends

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Q: Does it take 2 points to define a line segment?
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What is the geometric definition of a line?

If you take two points and you connect them, that is a line segment. A line stretches infinitely in two directions.


Why is there no such thing as 2 sided polygons?

actually, there is, depending on your definition of polygon, and your definition of a line segment. A line segment is the shortest path btwn two points, right? So take a sphere and pick any two points on that sphere. The shortest path between them on the surface of the sphere would be a "curve" along the surface, but it's the shortest path between the points, so it technally is a line segment. Take two of these line segments that intersect at two points, and there is your two sided polygon!


How would you find the distance between two points if the line segment that connects them horizontal?

Add the x-coordinates of the points and take the absolute value


How would you find the distance between two points if the line segment that connects them were vertical?

Subtract the y-coordinates of the points and take the absolute value


How can you construct a parallelogram?

Use two line segments (line A and line B) with all points on line A equidistant from all points on line B; in otherwords, use 2 parallel lines. Choose two points on line A (points a and b). Now choose 2 points on line B (x and y) so that the distance of line ab equals the distance of line xy. Connect points a and y with a line segment ab and points b and z with a line segment bz. In simpler words, take two parallel line segments of equal length, and connect their endpoints with two other line segments.


What is the measurement of a line segment?

You take the two endpoints of a line segment, and use the distance formula on it. The distance formula is the square root of (x1-x1)2 + (y1-y2)2


How do you find the distace of two points if the line segment that connects them were horizontal?

Simply take the difference betwen the two x coordinates.


What is the chord of a circle?

Take any circle and draw a straight line through it anywhere so that the line intersects the circle at two distinct points. The segment between the two points on the circle is the chord. A diameter, that is, a line segment through the center, could be a chord. But any shorter segment drawn through the circle and intersecting the circle at those two distinct points is a chord. It's just that simple. Need a link? You'll find one below.


How do you find midpoint of a segment?

Take a compass, extend it about 3/4 of the length of the segment. Then from one end of the segment, draw a 180 degree arc. From the other end draw another arc. Connect the points where the arcs intersect. Where the line intersects with the segment is the midpoint of the segment. That is how you bisect a segment to find the midpoint - geometrically.


How do you construct 90 degree angle with compass with construction steps?

Draw a line segment and with compass do the following, 1. Take more than half of line segment in compass. 2. From the left end point draw arc on the upper side and lower side of line segment. 3. Draw arc in the same way from right end point such that the arc should cut the arc from left end point . 4. Now join the points in the upper and lower side of the segment where the arcs drawn from left and right end points intersect. 5.you will get perpendicular bisector [ angle of 90 ]


What is the difference between convex polygon and non convex polygon?

A polygon is convex if you can take any two points inside the polygon and connect them with a line segment that is completely contained by the polygon. A non-convex polygon is one which contains at least two points such that the line joining them does not lie entirely inside the polygon.


How would you find the distance between two points if the line segment that connects them were horizontal?

Subtract the x-coordinates of the points and take the absolute value. Using the Pythagorean Theorem, the y-value would be zero, and the distance the square root of its own square.