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The points on the perpendicular bisector of a segment are equidistant from the segment's endpoints. This means that if you take any point on the perpendicular bisector, it will be the same distance from both endpoints of the segment. Additionally, the perpendicular bisector is a line that divides the segment into two equal parts at a right angle.

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2d ago

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What describes the Locus of all points that are equidistant from 2 lines?

The perpendicular bisector of the line joining the two points.


is this statement true or falseA perpendicular bisector is the set of points that are equidistant from the endpoints of the bisected segment.?

true


Are any points on the perpendicular bisector of a segment equally distant from the 2 endpoints?

All of the points on a perpendicular bisector are equidistant from the endpoints of the segment.


What is a characteristic of a perpendicular bisector?

Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.


What is the locus of points equidistant from two points?

The perpendicular bisector of the straight line joining the two points.


If R and S are two points in the plane the perpendicular bisector of RS is the set of all points equidistant from r and a?

The perpendicular bisector of a segment RS is the line that is perpendicular to RS at its midpoint and divides the segment into two equal parts. Any point on this bisector is equidistant from points R and S, meaning the distance from a point on the bisector to R is the same as the distance to S. This property makes the perpendicular bisector a key concept in geometry, especially in constructions and proofs involving distances and triangles.


What is the locus point equidistant from two points AB that are 8 cm apart?

The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.


If a and b are two points in the plane the perpendicular bisector of ab is the set of all points equidistant from a to b?

The perpendicular bisector of the line segment connecting points ( a ) and ( b ) in a plane is a line that is perpendicular to the segment at its midpoint. This line consists of all points that are equidistant from ( a ) and ( b ). Therefore, if any point lies on the perpendicular bisector, it maintains equal distance from both points. This property is fundamental in geometry and is used in various applications, including triangulation and construction.


What is the difference between a perpendicular line and a perpendicular bisector?

A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.


If R and S are two points in the plane the perpendicular bisector of is the set of all points equidistant from R and S.?

The perpendicular bisector of the line segment connecting points R and S is a line that is perpendicular to the segment at its midpoint. Any point on this line is equidistant from R and S, meaning the distance from any point on the bisector to R is the same as the distance to S. This property makes the perpendicular bisector a crucial concept in geometry, particularly in triangle construction and circle definition.


If R and S are two points in the plane the perpendicular bisector of line RS is the set of all points equidistant from R and S?

The perpendicular bisector of a line segment RS is a line that is perpendicular to RS at its midpoint. This line consists of all points that are equidistant from both points R and S. Thus, any point on this bisector will have the same distance to R as it does to S. It serves as a geometric locus of points maintaining this equal distance property.


In a circle the perpendicular bisector of a chord must pass through the center of the circle?

Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.