Want this question answered?
1600
For a cuboid it gives its volume.
I think you are asking how do you calculate the VOLUME of a disk 250mm with a thickness of 20 mm. If that is so, then find the area of the circle using the Area = pi times radius squared formula and then multiply by the thickness to get cubic millimeters volume.
the volume increase 8 times
It equals volume that is calculated in cubic units.
its weight divided by its volume. the volume is the circumference times thickness
Its volume is 200 cm3 for every centimeter of thickness.(You haven't mentioned what the book's thickness is.)
it is the volume
A surface area and a volume are qualitatively different. If for some body the surface area and the volume are numerically equal in one unit of measurement, then in another unit of measurement they won't be the same. For example, a cube of 6 m x 6 m x 6 m cube has a a volume of 216 cubic meters, and an area of 216 square meters, but if you calculate volume and surface area in cubic centimeters, the volume is a number that is 100 times greater.
volume The 'Volume' of an object or space
First you can use the volume to determine the side legnth of a cube. The legnth of a sideis equal to the cube root of its volume. In this case the volume is 125 and the cubed root of 125 is 5. So the legnth of a side is 5. The area of one side of the cube is equal to the width times the height. In this case, the area of the side is 5 times 5, or 25. The surface area is the area of all sides of the cube. The cube has 6 sides, each with an area of 25. So the surface area is 6 times 25 or 150. The reduced equation would be SA = 6 times (Volume to the 2/3 power)
No. Density is mass divided by volume.
1600
The volume of a hemisphere is equal to two thirds times pi times the radius cubed.
Volume is 4/3 pi*radius*radius*radius 3.14 times 7 times 7 times 7 times 4 divided by 3= volume 1436.2666666 Surface area is 4 * pi * radius * radius 4 times 3.14 times 7 times 7=surface area 615.44
Estimate the thickness of the soil over the area (test pits will help with this) - measure the average density of the soil (out of the test pits). You then have:- The "area" tiles the "thickness" = the volume of soil. Volume times density = weight.
volume is equal to four thirds pie times the radius cubed.