Q: Express 39 as a product of prime factors?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

39 = 3 x 13

As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39

3 x 13 = 39

39 = 3 x 13.

The product of its prime factors which are: 3*13 = 39

Related questions

39 = 3 x 13

As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39

39 = 3 x 13.

3 x 13 = 39

To find the HCF of two numbers you first have to express them as a product of their prime factors. In this case: 15 = 3x5 39 = 3x13 The next step is to identify any common prime factors. In this case, both numbers have 3 as a prime factor. Therefore the HCF of 15 and 39 is 3.

3 x 13 = 39

The product of its prime factors which are: 3*13 = 39

The product of the prime factors of any number is equal to the number itself. In the case of 117, its prime factorization is 32 x 13.The prime factors are: 3 and 13. (3 x 13 = 39)

The factors of 39 are: 1 3 13 39 The prime factors are: 3 and 13

The factors of 39 are 1, 3, 13, and 39. Its prime factors are 3 x 13. The factors of 51 are 1, 3, 17, and 51. Its prime factors are 3 x 17.

13 and 3The prime numbers (factors) of 39 are: 3 and 13

The prime numbers (factors) of 39 are: 3 and 13