39 = 3 x 13
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
3 x 13 = 39
39 = 3 x 13.
The product of its prime factors which are: 3*13 = 39
39 = 3 x 13
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
3 x 13 = 39
39 = 3 x 13.
To find the HCF of two numbers you first have to express them as a product of their prime factors. In this case: 15 = 3x5 39 = 3x13 The next step is to identify any common prime factors. In this case, both numbers have 3 as a prime factor. Therefore the HCF of 15 and 39 is 3.
To express the number 39 as a product of prime factors, we first identify that 39 is an odd number. We can start by dividing 39 by the smallest prime number, which is 2. Since 39 is not divisible by 2, we move on to the next prime number, which is 3. Dividing 39 by 3 gives us 13, which is a prime number. Therefore, the prime factorization of 39 is 3 x 13.
The product of its prime factors which are: 3*13 = 39
The product of the prime factors of any number is equal to the number itself. In the case of 117, its prime factorization is 32 x 13.The prime factors are: 3 and 13. (3 x 13 = 39)
The factors of 39 are: 1 3 13 39 The prime factors are: 3 and 13
The factors of 39 are 1, 3, 13, and 39. Its prime factors are 3 x 13. The factors of 51 are 1, 3, 17, and 51. Its prime factors are 3 x 17.
13 and 3The prime numbers (factors) of 39 are: 3 and 13
The prime numbers (factors) of 39 are: 3 and 13