3 x 13 = 39
39 = 3 x 13.
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
39 = 3 x 13
3 x 13 = 39
To write 39 as a product of primes, you need to factor it into its prime components. Start by dividing 39 by the smallest prime number, which is 3: (39 \div 3 = 13). Since 13 is also a prime number, the prime factorization of 39 is (3 \times 13). Thus, 39 can be expressed as the product of primes: (3 \times 13).
39 = 3 x 13.
To express the number 39 as a product of prime factors, we first identify that 39 is an odd number. We can start by dividing 39 by the smallest prime number, which is 2. Since 39 is not divisible by 2, we move on to the next prime number, which is 3. Dividing 39 by 3 gives us 13, which is a prime number. Therefore, the prime factorization of 39 is 3 x 13.
As a product of its prime factors: 2*2*3*3 = 36 or as 22*32 = 36 As a product of its prime factors: 3*13 = 39
3 x 13 = 39
39 = 3 x 13
To write 39 as a product of primes, you need to factor it into its prime components. Start by dividing 39 by the smallest prime number, which is 3: (39 \div 3 = 13). Since 13 is also a prime number, the prime factorization of 39 is (3 \times 13). Thus, 39 can be expressed as the product of primes: (3 \times 13).
13*3
The product of its prime factors which are: 3*13 = 39
2 x 3 x 13 is the answer. 78 is easily divisible by 2 so that makes 2 and 39. Then 39 becomes 3 and 13.
The product of the prime factors of any number is equal to the number itself. In the case of 117, its prime factorization is 32 x 13.The prime factors are: 3 and 13. (3 x 13 = 39)
The factors of 39 are: 1 3 13 39 The prime factors are: 3 and 13
13 and 3The prime numbers (factors) of 39 are: 3 and 13