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b3 - 5b2 + 12 = (b - 2)(b2 - 3b - 6)
Check:
(b - 2)(b2 - 3b - 6)
= b(b2 - 3b - 6) - 2(b2 - 3b - 6)
= b3 - 3b2 - 6b - 2b2 + 6b + 12
= b3 - 5b2 + 12
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∙ 13y ago
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