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Kyleigh Kling
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∙ 13y agowrite the whole problem
if it was b6 (raised to six) * 36 then it would be (b3-6)(b3+6)
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Who can factor 64a raised to 6n - b raised to 6n?
n(2a - b)(2a + b)(4a^2 - 2ab + b^2)(4a^2 + 2ab + b^2)
Factor 3ab - a - 3b squared plus b?
6
What is the expression for a number used a factor seventeen times being multiplied by a number used as a factor fourteen times?
a^17 x b^14 where ^ means "raised to the power of.."
How do you find all the factors for a number without listing them all?
It is not simple. The only systematic way is to find the prime factorisation of the number and write it in exponential form. So suppose n = (p1^r1)*(p2^r2)*...*(pk^rk) where p1, p2, ... pk are prime numbers and rk are the indices (or powers). Then the factors of n are (p1^s1)*(p2^s2)*...*(pk^sk) where 0 ≤ sk ≤ rk. And remember that anything raised to the power 0 is 1. Example: n = 72 = 2*2*2*3*3 = (2^3)*(3^2) so, the factors of n are (2^a)*(3^b) where a = 0, 1, 2 or 3 and b = 0, 1 or 2. When (a, b) = (0, 0) the factor is 1. (a, b) = (1, 0) the factor is 2. (a, b) = (2, 0) the factor is 4. (a, b) = (3, 0) the factor is 8. (a, b) = (0, 1) the factor is 3. (a, b) = (1, 1) the factor is 6. (a, b) = (2, 1) the factor is 12. (a, b) = (3, 1) the factor is 24. (a, b) = (0, 2) the factor is 9. (a, b) = (1, 2) the factor is 18. (a, b) = (2, 2) the factor is 36. (a, b) = (3, 2) the factor is 72.
How do you factor 30b2 plus 48b-24?
6(b + 2)(5b - 2)
Who can factor 64a raised to 6n - b raised to 6n?
n(2a - b)(2a + b)(4a^2 - 2ab + b^2)(4a^2 + 2ab + b^2)
What is the greatest common factor 6 B and B?
The GCF is 1.
Factor 3ab - a - 3b squared plus b?
6
How do you factor 6a 6b?
6a + 6b = 6(a + b)
What is the expression for a number used a factor seventeen times being multiplied by a number used as a factor fourteen times?
a^17 x b^14 where ^ means "raised to the power of.."
How do you find all the factors for a number without listing them all?
It is not simple. The only systematic way is to find the prime factorisation of the number and write it in exponential form. So suppose n = (p1^r1)*(p2^r2)*...*(pk^rk) where p1, p2, ... pk are prime numbers and rk are the indices (or powers). Then the factors of n are (p1^s1)*(p2^s2)*...*(pk^sk) where 0 ≤ sk ≤ rk. And remember that anything raised to the power 0 is 1. Example: n = 72 = 2*2*2*3*3 = (2^3)*(3^2) so, the factors of n are (2^a)*(3^b) where a = 0, 1, 2 or 3 and b = 0, 1 or 2. When (a, b) = (0, 0) the factor is 1. (a, b) = (1, 0) the factor is 2. (a, b) = (2, 0) the factor is 4. (a, b) = (3, 0) the factor is 8. (a, b) = (0, 1) the factor is 3. (a, b) = (1, 1) the factor is 6. (a, b) = (2, 1) the factor is 12. (a, b) = (3, 1) the factor is 24. (a, b) = (0, 2) the factor is 9. (a, b) = (1, 2) the factor is 18. (a, b) = (2, 2) the factor is 36. (a, b) = (3, 2) the factor is 72.
What is the greatest common factor of B 48 and 54?
That would depend on the value of B. The answer will be 1, 2, 3 or 6.
How do you factor 30b2 plus 48b-24?
6(b + 2)(5b - 2)
Is b plus 4 a factor of b3 plus 3b2 minus b plus 12?
3 times a times a times b
How do you factor ab plus 2a plus 3b plus 6?
(a + 3)( b + 2)
How do you factor ab plus 3a-2b-6?
(a - 2)(b + 3)
What is the Factor of b2- 6b -16?
(b + 2)(b - 8)
