(x+7)(x+12)
(x + 12)(x + 7)
2(4x - 1)(5x - 6)
x2 + 8x + 12 = (x + 6) (x + 2)
x2-14x+24=(x-12)(x-2) Since there are no options listed in this question ;), the answer could be either "x-12" or "x-2". How to factor a trinomial: see link.
(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
5x2-16x+12 = (5x-6)(x-2) when factored
(x + 6)(x + 2)
There is no rational factorisation of 6y2 + 19y - 13 The roots are [-19 +/- sqrt(673)]/12 which are -3.74519 and 0.57852
(x + 2)(x - 12)
x^2 - 8z - 48 Factor ( x - 12)(x + 4)
24 = 2 x 12 or 3 x 8 or 4 x 6: Only 3 & 8 total 11 so factors are (x + 8)(x + 3)