x2 + 8x + 12 = (x + 6) (x + 2)
(x + 6)(x + 2)
x + 4
x^2 - 8z - 48 Factor ( x - 12)(x + 4)
(x - 11)(x + 3)
(x + 6)(x + 2)
This would be easier with operational signs but assuming everything is added together, the answer is (8x + 9)(8x + 9) or (8x + 9)2
x2-8x+12 = (x-2)(x-6) when factored
A factor of a perfect square trinomial is eithera number that is a factor of each term of the trinomial,a binomial that is a factor of the trinomial, ora product of the above two.For example, consider 4x2 + 8x + 4It has the factors2 or 4,(x + 1) or2x+2 = 2*(x+1) or 4x+4 = 4*(x+1)
That does not factor neatly.
(x - 6)(x - 2)
-8x + 3x2 - 3
By inspection. X^2 - 8X - 33 (X - 11)(X + 3) FOIL and see. X = 11 X = - 3