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Factor the trinomial below Enter each factor as a polynomial x2 - 9x plus 18?
(x - 6)(x - 3)
What is the trinomial (3x plus 9)(3x plus 2)?
9x+3
Factor the trinomial 2x squared plus 9x7?
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
What is the factorization of the trinomial 2x squared plus 9x plus 9?
2x2+9x+9 = (2x+3)(x+3) when factored
Xsquared plus 9x plus 14 divided by x plus 5?
(x^2 + 9x +14) / (x+5) Factor (x^2 + 9x +14) [(x+7)(x+2)]/[(x+5)], x cannot equal -5
What is the factor trinomial 2x plus 7x plus 10?
10 + 9x
Factor the trinomial below Enter each factor as a polynomial x2 - 9x plus 18?
(x - 6)(x - 3)
Is 3x plus 3x plus 3x a trinomial?
No. It is 9x, which is a monomial.
What is the trinomial (3x plus 9)(3x plus 2)?
9x+3
Factor the trinomial 2x squared plus 9x7?
If you mean: 2x^2 +9x +7 then it is (2x+7)(x+1) when factored
What is the factorization of the trinomial 2x squared plus 9x plus 9?
2x2+9x+9 = (2x+3)(x+3) when factored
Xsquared plus 9x plus 14 divided by x plus 5?
(x^2 + 9x +14) / (x+5) Factor (x^2 + 9x +14) [(x+7)(x+2)]/[(x+5)], x cannot equal -5
How do you factor 102 plus 9x plus 4?
102 +9x +4 = 9x + 106, which is in its simplest form.
81x2 - 72x plus 16 is a perfect square trinomial true or false?
If a trinomial is a perfect square, then the discriminant will equal 0. The discriminant is equal to B^2-4AC. The variables come from the standard form of a quadratic which is Ax^2+Bx+C In this problem, A=81, B=-72, and C=16 so the discriminant is: (-72)^2-4(81)(16)=5,184-5,184=0 so this is a perfect square trinomial. To factor, notice that 81=9^2 and 16=4^2, so 81x^2=(9x)^2. We can then factor the trinomial into (9x+4)(9x-4)
9x plus 2 equals 12x plus 14?
9x + 2 = 12x + 14 -3x = 12 x = -4
How can you check your work when factoring a trinomial?
When factoring it is fairly easy to check your answer. Say we want to factor x2+9x+14=0 (x+7)(x+2)=0 now if we want to check then we can just multiply these together and we should get the original polynomial... x2+2x+7x+14=0 x2+9x+14=0
Factor 81x plus 9x?
You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
