You don't need to factor that; you can add them together, since they have the same variable.However, assuming you might mean 81x squared + 9x, you can take out the common factor, which is 9x.
sqrt(81x2)=9x*sqrt=square root of
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
9x + 1x = 10x.
x+5+3x-7+9x+3-4x Collect like terms: 9x+1
81x2 + 72x + 16 = 81x2 + 36x + 36x + 16 = 9x(9x + 4) + 4(9x + 4) = (9x + 4)2
82
Yes, the expression (9x^2 + 81x + 9) is a trinomial. A trinomial is defined as a polynomial with three terms, which in this case are (9x^2), (81x), and (9). Each term consists of a coefficient and a variable raised to a power, fitting the criteria for a trinomial.
If you mean (9x-8y)(9x+8y) then it is 81x^2 minus 64y^2
102 +9x +4 = 9x + 106, which is in its simplest form.
(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
sqrt(81x2)=9x*sqrt=square root of
9x^(2) + 16 DOES NOT factor. Remember ; two squared terms with a plus(+) between them DOES NOT factor However, two squared terms with a minus(-) between them DOES factor . Hence 9x^(2) + 16 = (3x)^2) + 4^(2) does NOT factor However, 9x^(2) - 16 = (3x)^2) - 4^(2) does factor to ( (3x - 4)(3x + 4) Note the two different signs.
10 + 9x
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
(2x + 1)(x + 4)
x^2-9x+18=(x-6)(x-3)
9x2 + 8x - 1 = (9x - 1)(x + 1)