(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
3x2+7-6 = (3x-2)(x+3) when factored
Factors are: 9(x - 1)(x - 1) or (3x - 3)2, so yes, it is.
3x + 2 = 3x + 6 This is not possible.
18x2 +12x + 2 this is not a perfect square trinomial so let's work a little bit here. 18x2 +12x + 2 factor 2 = 2(9x2 +6x + 1) = 2(3x + 1)2 represent 2 as (√2)2 = (√2)2(3x + 1)2 = [(√2)(3x + 1)]2 take its square root = (√2)(3x + 1) for all x > -1/3.
It is a quadratic expression and can be factored into: (3x+1)(x+2)
(3x+1)(x+2)
(3x - 2)(2x + 6) or 2(3x - 2)(x + 3)
(2x + 7)(x - 2)
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
3x^2 + 10x + 8 = (3x + 4)(x + 2)
3x2+7-6 = (3x-2)(x+3) when factored
Only if all the variables match up. Example of when they do match: 3x^2 +2y+r plus x^2- 2r+ 3y When they don't match: 3x^4+x+y plus 3x^3-x^2 +r
False. It has to be either "- 24x" or "+ 36". These would factor as (3x - 4)2 and (3x - 6)2 respectively.
Factors are: 9(x - 1)(x - 1) or (3x - 3)2, so yes, it is.
-(3x - 4)(x - 2)
13