1, 3, 7, 9, 21, 63
3 and 7 are prime.
The factors of 63 are: 1, 3, 7, 9, 21, 63. The prime factors of 63 are: 3, 7
The prime factors of 63 are 3 and 7.
The factors of 63 are: 1 3 7 9 21 63. The prime factors are: 3 and 7
The prime factors of 63 are: 3,7.3 x 3 x 7The prime numbers (factors) of 63 are: 3 and 73 and 73*3*7
As a product of its prime factors: 3*3*7 = 63
3 x 3 x 7 is 63 as the product of prime factors.
The 6 factors of 63 are 1, 3, 7, 9, 21, and 63. The factor pairs of 63 are 1 x 63, 3 x 21, and 7 x 9. The proper factors of 63 are 1, 3, 7, 9, and 21; possibly not 1, depending on your definition. The prime factors of 63 are 3, 3, and 7. The 2 distinct prime factors of 63 are 3 and 7.
63=3x3x7
Unless you specify a range, there will always be a number with more prime factors. As it is, 63 only has two of them.
No,Both have equal number of Prime factors.
The factorization of 63 involves breaking it down into its prime factors. It can be expressed as (63 = 3^2 \times 7), where 3 and 7 are prime numbers. Therefore, the prime factors of 63 are 3 and 7.
32=2^5=5 factors 63=3^2 x 7=3 factors 63 has fewer