32=2^5=5 factors
63=3^2 x 7=3 factors
63 has fewer
2 x 2 x 2 x 2 x 2 = 32 7 x 7 = 49 3 x 3 x 7 = 63 2 x 2 x 5 x 5 = 100 49 has the fewest prime factors. 32 and 49 have the fewest distinct prime factors.
49 has one distinct prime factor, two altogether.
49 has one distinct prime factor, two altogether.
63 does not have fewest prime factors. It is a product of 3, 3 and 7.
63 = 32 x 71
63 = 3*3*332 = 2*2*2*2*249 = 7*7100 = 2*2*5*5Out of these numbers 63,32 & 49 has only one prime factor.
63 = 9 x 7 = 32 x 7
It is 49 or 32 both of which have only one prime factor
63 = 9 x 7 which would be 32 x 71
The prime factors of 63 are 3 and 7.
The factors of 63 are: 1, 3, 7, 9, 21, 63. The prime factors of 63 are: 3, 7
Yes. You can find that out by adding one to the exponents of the prime factors and multiplying them. The prime factorization of 63 is 32 x 713 x 2 = 6