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Find the co-ordinate of points on the x-axis which are at a distance of 5 units from the point (6,-3)?
To find the coordinates of points on the x-axis that are 5 units away from the point (6, -3), we can use the distance formula. The distance formula is:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, we know that x1 = 6, y1 = -3, and distance = 5. We also know that the points are on the x-axis, so the y-coordinate is 0. So we can plug these values into the distance formula and solve for x2:
5 = √((x2 - 6)^2 + (0 - (-3))^2)
5 = √(x2 - 6)^2 + 9
25 = (x2 - 6)^2
x2 = √25 + 6 = √16 + 6 = 4 + 6 = 10
Therefore, the coordinates of the point on the x-axis that is 5 units away from (6, -3) in the positive direction of x-axis are (10, 0) and the point on the x-axis that is 5 units away from (6, -3) in the negative direction of x-axis is (2,0).
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