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Which line is perpendicular to x-3 and goes through the point (0-4)?
To find the line perpendicular to (x - 3), we first note that (x - 3) represents a vertical line, so a line perpendicular to it would be horizontal. The equation of a horizontal line that passes through the point ((0, -4)) is (y = -4). Thus, the line perpendicular to (x - 3) and passing through ((0, -4)) is (y = -4).
To find the equation of a line you must know at least one point through which the line passes and the slope of the line?
yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
How does using the point slope form a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point - slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point-slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
How does using the point slope form of a linear equation make it easier to write the equation of a line?
If given simply the slope of a line and a point through which it passes, and then told to find the equation of the line, one of the easiest ways of doing so is to use the point-slope formula.
What equation represents a line that has a slope of 2 and goes through the point (14)?
To find the equation of a line with a slope of 2 that passes through the point (1, 4), we can use the point-slope form of the equation: (y - y_1 = m(x - x_1)), where (m) is the slope and ((x_1, y_1)) is the point. Plugging in the values, we get (y - 4 = 2(x - 1)). Simplifying this, the equation of the line is (y = 2x + 2).
What is where the line crosses the horizontal axis?
The point where a line crosses the horizontal axis is called the x-intercept. At this point, the value of the y-coordinate is zero, meaning the line intersects the x-axis at that specific value of x. To find the x-intercept of a linear equation, you can set the y-value to zero and solve for x.
How you find the equation of a line give one point and is parallel to an equation?
i am cute
How do you find horizontal and vertical asymptotes?
finding vertical asymptotes is easy. lets use the equation y = (2x-2)/((x^2)-2x-3) since its a rational equation, all we have to do to find the vertical asymptotes is find the values at which the denominator would be equal to 0. since this makes it an undefined equation, that is where the asymptotes are. for this equation, -1 and 3 are the answers for the vertical ayspmtotes. the horizontal asymptotes are a lot more tricky. to solve them, simplify the equation if it is in factored form, then divide all terms both in the numerator and denominator with the term with the highest degree. so the horizontal asymptote of this equation is 0.
Can you find the slope of a horizontal line?
yes we can calculate it by using trigonometric equation (by finding tan θ).
Find the equation of straight line parallel to the line 5x+3y-1=0 and passing through the point (2,-1)?
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