yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!!
Good Luck!!!!!!!!!!!!!
An equation of a line that is parallel to the x-axis is a horizontal line, which has a constant y-value. Since the line passes through the point (15), it must have the same y-coordinate as that point. Therefore, if the point is (15, y), the equation of the line is (y = k), where (k) is the y-coordinate of the point. If the y-coordinate is not specified, the equation can be expressed as (y = b), where (b) is the y-value of the point through which it passes.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
414
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
sda
Assuming the point is (9, -4), the equation is y = -4.
An equation of a line that is parallel to the x-axis is a horizontal line, which has a constant y-value. Since the line passes through the point (15), it must have the same y-coordinate as that point. Therefore, if the point is (15, y), the equation of the line is (y = k), where (k) is the y-coordinate of the point. If the y-coordinate is not specified, the equation can be expressed as (y = b), where (b) is the y-value of the point through which it passes.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
The equation is: y = 4x-22
414
The equation works out as: y = 5x+7
If you mean a slope of 6 passing through the point of (1, 3) then the equation works out as: y = 6x-3
"14" is not a point; you need two coordinates to specify a point.
If you mean a slope of 6 and point of (-3, 5) then the equation is: y = 6x+23
If you mean slope of -3 and a point of (2, 4) then the equation is y = -3x+10