infinitely far
40cm2
The perimeter of a rectangle is calculated by adding together the lengths of all its sides. In this case, the rectangle has two sides of length 10cm and two sides of length 3cm. Therefore, the perimeter is calculated as 10cm + 10cm + 3cm + 3cm = 26cm.
10 × 5 = 50Therefore, the width is 5 centimetres.
area = length x width area = 12 x 10 = 120 square cm
sqrt( 102 + 242 ) = sqrt( 100+ 576 ) = sqrt( 676 ) = 26 cm
Use Pythagoras . d^(2) = l^(2) + w^(2) Substituting d^(2) = 24^(2) + 10^(2) d&(2) = 576 + 100 d^(2) = 676 Square root both sides d = sqrt)676_ d = 26 cm
40cm2
Width = 10cm.. i think Length = 68cm
You question is does not make sense. The base is a straight line , NOT an area. You either want the Area of the rectangle or the Length of the base. The Area of a rectangle is found by multiplying the base (length) to the width(height). A = lW (or BH) Algebraically rearrange to find the base length B = A/H ( That is area divided by height).
The perimeter of a rectangle is calculated by adding together the lengths of all its sides. In this case, the rectangle has two sides of length 10cm and two sides of length 3cm. Therefore, the perimeter is calculated as 10cm + 10cm + 3cm + 3cm = 26cm.
10 × 5 = 50Therefore, the width is 5 centimetres.
area = length x width area = 12 x 10 = 120 square cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
sqrt( 102 + 242 ) = sqrt( 100+ 576 ) = sqrt( 676 ) = 26 cm
The volume of a solid rectangle is equal to Length x Width x Height. So, 20cm x 10cm x 5cm would be 1000cm cubed.
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm