Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
Divide the known perimeter by 2... giving 23. 23 - 5 = 18. 18 /2 = 9. 9 + 5 = 14 ! To confirm the answer... 14 + 14 + 9 + 9 = 46.
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
P of rectangle = 2(L+W) where L=W+6 24 = 2(W+(W+6)) 12 = W+ W+ 6 6 = 2 W 3 = W The length (W+6) is 9, width (W) is 3.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
10x2
width=5 length=12
Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
the perimeter of a rectangle is 700 yards. what are the dimensions of the rectangle if the lenght is 80 yards more than the width?
You forgot to put in the length of the rectangle's perimeter.
w=8in l=13in
length + width = 20/2 = 10 length = 7cm, width = 3cm
Length = 20 m and width = 9 m
The dimensions of the rectangle are 21 units by 9 units
6
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.