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What is the width and length of a rectangle if the perimeter is 50 and the length is 5 cm more than the width?
Wiki User
∙ 12y ago
Perimeter = 2 lengths and 2 widths
In your case length + width = 25cm
If length is 5cm more than width then length = 15cm and width = 10cm
Wiki User
∙ 12y ago
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The length of a rectangle is 3 inches more than its width and its perimeter is 22 inches Find the width of the rectangle?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
The perimeter of a rectangle is 130m. The length of the rectangle is 25m more than the width. What are the lengths and widths of the rectangle?
x=width x+25=length 4x+50=130 4x=80 x=20 width is 20 length is 45
The length of a rectangle is 5cm more than its width The perimeter of the rectangle is 46 What is the length of the rectangle?
Divide the known perimeter by 2... giving 23. 23 - 5 = 18. 18 /2 = 9. 9 + 5 = 14 ! To confirm the answer... 14 + 14 + 9 + 9 = 46.
What is The length of a rectangle is 4 cm more than the width and the perimeter is at least 48 cm. What are the smallest possible dimensions for the rectangle?
The dimensions of the rectangle will then work out as 14 cm by 10 cm because the perimeter is 14+10+14+10 = 48 cm
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P of rectangle = 2(L+W) where L=W+6 24 = 2(W+(W+6)) 12 = W+ W+ 6 6 = 2 W 3 = W The length (W+6) is 9, width (W) is 3.
The length of a rectangle is 5 more then the width Find the perimeter and the area of the rectangle?
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Let the width of rectangle is w cm (Length is 12 cm more) so length is w + 12 Perimeter = 16 times of width 2 (length + width) = 16 * width Rest of the homework, do yourself.
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You forgot to put in the length of the rectangle's perimeter.
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w=8in l=13in
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length + width = 20/2 = 10 length = 7cm, width = 3cm
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6
The length of a rectangle is 3 inches more than its width and its perimeter is 22 inches Find the width of the rectangle?
Perimeter = length + width + length + width = 2 x (length + width) Given: perimeter = 22in length = width + 3in Thus 22 = 2 x (width + 3 + width) 11 = 2 x width + 3 8 = 2 x width 4 = width So the width is 4in.
