The diagonal is 26cm
40cm2
10 × 5 = 50Therefore, the width is 5 centimetres.
area = length x width area = 12 x 10 = 120 square cm
sqrt( 102 + 242 ) = sqrt( 100+ 576 ) = sqrt( 676 ) = 26 cm
The diagonal is 26cm
40cm2
Width = 10cm.. i think Length = 68cm
In order to find the area of a rectangle, multiply the length by the width of the rectangle. For example: If the length of a rectangle is 5cm and the width of a rectangle is 2cm, then the area of the rectangle would be 5cm X 2cm = 10cm².
10 × 5 = 50Therefore, the width is 5 centimetres.
area = length x width area = 12 x 10 = 120 square cm
Perimeter = 2 lengths and 2 widths In your case length + width = 25cm If length is 5cm more than width then length = 15cm and width = 10cm
sqrt( 102 + 242 ) = sqrt( 100+ 576 ) = sqrt( 676 ) = 26 cm
The volume of a solid rectangle is equal to Length x Width x Height. So, 20cm x 10cm x 5cm would be 1000cm cubed.
First find the dimensions of the rectangle. Let its length be 2x and its width be x: 2(2x+x) = 60 4x+2x = 60 6x = 60 x = 10 Therefore: length = 20cm and the width = 10cm Area = length*width Area = 200cm2
Using Pythagoras the length of the diagonal in the rectangle is the square root of 149 or just over 12 cm
I assume you are referring to a rectangle. Just add the lengths of all four sides.