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Q: Find 3 consecutive odd numbers where the product of the smaller two numbers is 34 less than the square of the largest number.?

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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

5,6,7

11,12,13

8,10,12

5, 6 and 7

8, 9, and 10

12, 13 and 14

1, 3, 5

16, 17 and 18

14, 15, 16

4, 6, and 8

8, 10, 12

3, 5, 7

5, 6, 7

4, 6, and 8

4,6,8

the answer is 6

Five, six and seven. (Check the math, so you can be sure!)

I hope you meant "product of smaller two"! 5 x 6 = 30, 72 = 49

Surely the question is wasn't meant to say what it literally said, but a solution to its literal statementis still possible.The two consecutive numbers are: 18 and 19.The smaller two numbers are: 18 and 19.Their product is 342 .The largest number is 19.Its square is 361.342 is 19 less than 361.

The three numbers are 6, 8, and 10. 102 - 8 x 6 = 52

The three numbers are 10, 9, and 8: 102 - (9 x 8) = 28

This isn't possible. They'd have to be even (8, 10, 12).

4,6,8,10

The product of 2 consecutive positive number is 48. Find the 2 numbers