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16, 17 and 18

Q: Find 3 consecutive numbers where the product of the smaller two numbers is 52 less than the square of the largest number?

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8,10,12

the answer is 6

6 and 8. 6 * 8 = 48 6 * 6 = 36 48 - 36 = 12

Let the 3 consecutive number be represented by n, (n + 1) and (n + 2) Then, n(n + 1) + 37 = (n + 2)2 n2 + n + 37 = n2 + 4n + 4 3n = 33 n = 11 The three numbers are 11, 12 and 13.

i would do trial and error; 7x9=63 11x11=121 difference of 58, which is too big, so try 3x5=15 7x7=49, difference of 34, again too big 1x3=3 5x5=25 difference of 22 answer=1,3,5

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