16, 17 and 18
8,10,12
the answer is 6
6 and 8. 6 * 8 = 48 6 * 6 = 36 48 - 36 = 12
Let the 3 consecutive number be represented by n, (n + 1) and (n + 2) Then, n(n + 1) + 37 = (n + 2)2 n2 + n + 37 = n2 + 4n + 4 3n = 33 n = 11 The three numbers are 11, 12 and 13.
i would do trial and error; 7x9=63 11x11=121 difference of 58, which is too big, so try 3x5=15 7x7=49, difference of 34, again too big 1x3=3 5x5=25 difference of 22 answer=1,3,5
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
5,6,7
11,12,13
8,10,12
8, 9, and 10
12, 13 and 14
1, 3, 5
14, 15, 16
4, 6, and 8
8, 10, 12
3, 5, 7
5, 6, 7