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Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

Q: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.?

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11,12,13

3, 5, 7

trial and error; 5x7=35 9x9=82, difference of 47. not big enough difference. 7x9=63 11x11=121. differenence of 58, which is too big. sorry, but this means there is not answer.

6, 8, and 10. To figure this one out, it is trial and error, so pick random numbers. 4x6=24 8x8=64, difference of 40, not big enough. 6x8=48 10x10=100 difference of 52. So, the right answer is 6, 8, and 10.

4,6,8,10ok, that's kool, now what the hell is the answer to this mind blower?!?!The square of 9 more than a number is equal to 9 more than the square of the number What is the number? the answer is 10,8,6 and 4

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