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The four numbers will be 2n, 2(n + 1), 2(n + 2), and 2(n + 3), such that:

2 * 2n + 2(n + 3) = 96

6n = 90

n = 15

So the four numbers are 30, 32, 34, and 36

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Q: Find 4 consecutive even integers such that twice the least increased by the greatest 96?
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