you need to phrase this question better. Are you trying to solve for a voltage drop in a length of wire or are you trying to size the wire for some application?
It depends on the voltage-- I think at 110v it's 4 amps per hp
"Amps" is a steady thing. There's no such thing as "Amps per hour".The current through a 24-watt load is[ 24/the voltage across the load ] Amperes.
To obtain amps from watts a voltage must be given.
To answer this question the voltage of the generator must be given.
50 kVA is 16.667 kVA per phase and you divide that by the phase voltage. Current = 16667 / 277 = 60 Amps
Without knowing the resistance present or the power being consumed, it is not possible to determine how volts are present in a circuit with 63 amps. Ohm's Law: Voltage = Current times Resistance Volt: Joules per CoulombAmpere: Coulombs per SecondWatt: Joules per Second
kilo... means x1000 so... 1000000 or a Million Watts, or 1to the 6 booyakasha!
Watts = amps x volts x Power Factor. Power Factor comes into play when there are non-resistive loads involved. If you assume a maximum PF = 1 and a 120 volt source then Amps per Watt = 1/120 = .083
Assuming we are talking about 2300 BTU per hour, take 2300 and divide by the number of BTUs per watt-hour, 3.414, giving 673 watts. Then divide this by the voltage, 240, giving 2.81 amps.
current is the rate of flow of charge: colombs per second or amps voltage is the amount of energy in one colomb of charge: volt or jouls per colomb voltage times current is the power.
For lighting using CFL bulbs you can use 10 square feet per watt. The volt-amps is the volts times the amps, or the watts divided by the power factor. Most CFL bulbs are marked with the voltage and the current.
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