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The altitude of an equilateral triangle bisects the base.

So, if the sides of the triangle were l cm, the altitude forms a right angled triangle with sides h, l/2 and hypotenuse l cm.

Then, by Pythagoras, h2 = 3l2 / 4 so that h = l*sqrt(3)/2

and then area = l*h/2 = l*[l*sqrt(3)/2]/2 =l2*sqrt(3)/4

Q: Find the area of an equilateral triangle with altitude h cm?

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35.074 units2

It is double the length of the base, in square units.

The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2

If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.

Area of a triangle = 1/2*base*altitude in square units Area = 45 square feet

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Area = 0.5*base*altitude

35.074 units2

Do you mean an equilateral triangle? Then if so then the formula for the area of any triangle: 0.5*a*b*sinC whereas a and b are the embraced sides of angle C And in the case of an equilateral triangle it is: 0.5*any side squared*sin(60 degrees) Alternatively use Pythagoras' theorem to find the altitude of the triangle then use: 0.5*base*height = area

It is double the length of the base, in square units.

Find the area of an equilateral triangle if its perimeter is 18 ft

altitude(height)=(Area * 2) /length(Base)

The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2

Area of Equilateral Triangle A= S2 * (Root 3)/4, where A= Area of the triangle S= Side of the triangle.

Find the area of an equilateral triangle that has a perimeter of 21 inches. Round the answer to one decimal place.

Area of an equlateral triangle = 0.5*side2*sin(60)

Finding the perpendicular height of the triangle by using Pythagoras works out at about 8.660254038. 1/2*base*perpendicular height or altitude = area 1/2*10*8.660254038 = 43.30127019 square units

Area = 1/2*altitude*base Area = 1/2*17.32050808*20 Area = 173.2050808 square inches The altitude or height was worked out by using Pythagoras' theorem.