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The altitude of an equilateral triangle bisects the base.
So, if the sides of the triangle were l cm, the altitude forms a right angled triangle with sides h, l/2 and hypotenuse l cm.
Then, by Pythagoras, h2 = 3l2 / 4 so that h = l*sqrt(3)/2
and then area = l*h/2 = l*[l*sqrt(3)/2]/2 =l2*sqrt(3)/4
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What is the area of an equilateral triangle that has an altitude of 9?
35.074 units2
What is the area of an equilateral triangle whose altitude is 4?
It is double the length of the base, in square units.
What is the formula for finding altitude and area of equilateral triangle?
The altitude formula is like this: Area x 2 divided by the base ( Ax2:b) The area formula is base x height divided by 2
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If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
What is the perimeter and area of an equilateral triangle with a side of 8?
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