altitude(height)=(Area * 2) /length(Base)
The triangle's altitude is 8.7 (8.66025) cm.
Here are a couple Find the altitude of a triangle with base 3 and hypotenuse 5. Find the altitude of an equilateral triangle with each side to 2
The altitude of a triangle is the distance from the line containing the base to the vertex. Draw the base and continue on outside of the triangle. Measure perpendicular from that line to the vertex.
28.75m
By using Pythagoras' theorem.
Altitude = 10.4 (10.3923) cm
By using Pythagoras' theorem.
Half base x altitude...
To find the altitude of a triangle, we can use the formula: area = 0.5 * base * altitude. Given that the area is 45 cm² and the base is 15 cm, we can plug these values into the formula: 45 = 0.5 * 15 * altitude. Solving for altitude, we get altitude = 45 / (0.5 * 15) = 45 / 7.5 = 6 cm. Therefore, the altitude of the triangle is 6 cm.
The altitude of a triangle is measured perpindicular to its base.
The altitude of an equilateral triangle is (√3)/2*a. where 'a' is the side of the triangle. It can be just find by giving a perpendicular to the base of the triangle, the base of the triangle become a/2 and one side is a. so by applying Pythagoras theorem we will get the desired formula.
You can find it by using the Pythagorean theorem if you know the side and the base of triangle. In an isosceles triangle the median is also the altitude. The formula is: (The measure of the side length)^2 - (The measure of the one half of the base length )^2 = (The measure of the altitude)^2. Find the square root of the result that you'll have the measure of the altitude.