Do your homework dude.......
By definition, a monomial has only one unknown independent variable, usually represented by a letter of the alphabet. The exponent immediately after that symbol for the unknown is the degree of the monomial.
The degree of a monomial is the sum of the exponents. Example: 28x3yn2. Although the letters are different, the degree is 3+1+2. The 1 is understood above the y. So the degree is 6. The degree of anything besides a monomial is the highest degree of the other monomials. For example: 77a3b5c6+100xyz. | | 3+5+6 1+1+1 14 3 Although the 100 is the bigger number, the degree of this binomial is 14. The same is for a trinomial etc. You just find the degree of all monomials. The highest degree is the degree the whole binomial/trinomial ect. I hope I helped!
the answer is 3x2
You find the center of a screwed 45 degree elbow by bisecting the angle.
By counting.
By definition, a monomial has only one unknown independent variable, usually represented by a letter of the alphabet. The exponent immediately after that symbol for the unknown is the degree of the monomial.
The degree of a monomial is the sum of the exponents. Example: 28x3yn2. Although the letters are different, the degree is 3+1+2. The 1 is understood above the y. So the degree is 6. The degree of anything besides a monomial is the highest degree of the other monomials. For example: 77a3b5c6+100xyz. | | 3+5+6 1+1+1 14 3 Although the 100 is the bigger number, the degree of this binomial is 14. The same is for a trinomial etc. You just find the degree of all monomials. The highest degree is the degree the whole binomial/trinomial ect. I hope I helped!
12ab
6y6
the answer is 3x2
You need at least two terms to find an LCM.
Find the gcf for the coefficients and find the smallest exponential for the variable(s), but the variable must be in all the monomial terms.
To find the GCF of each pair of monomial of -8x³ and 10a²b², we can use the following steps: Write the complete factorization of each monomial, including the constants and the variables with their exponents. -8x³ = -1 ⋅ 2 ⋅ 2 ⋅ 2 ⋅ x ⋅ x ⋅ x 10a²b² = 2 ⋅ 5 ⋅ a ⋅ a ⋅ b ⋅ b Identify the common factors in both monomials. These are the factors that appear in both factorizations with the same or lower exponent. The common factors are: 2 Multiply the common factors to get the GCF. GCF = 2 Therefore, the GCF of each pair of monomial of -8x³ and 10a²b² is 2.
1. Quadratic Formula 2. Rational Root Theorem 3. Zero Product Theorem
To find the GCF of each pair of monomials of 10a and lza²b, we can use the following steps: Write the complete factorization of each monomial, including the constants and the variables with their exponents. 10a = 2 ⋅ 5 ⋅ a lza²b = lz ⋅ a ⋅ a ⋅ b Identify the common factors in both monomials. These are the factors that appear in both factorizations with the same or lower exponent. The common factors are : a Multiply the common factors to get the GCF. GCF = a Therefore, the GCF of each pair of monomial of 10a and lza²b = a
Complete the square is the process of creating a "perfect square" polynomial. We call (x + a)^2 a perfect square, where a is a constant. Using simple distributivity of numbers, we get x^2 + 2ax + a^2 is a representation of a perfect square in simplified formed. so (x + a) ^2 = x^2 + 2ax + a^2. Given a degree polynomial in the form x^2 + nx, where m and n are constants, when we "complete the square", we are looking for values that will turn it into something like x^2 + 2ax + a^2. The entire idea is to find what "a" is. 2a is the coefficient for the degree one monomial "2ax" for what we want, also n is the coefficient for the degree one monomial "nx" for what we have. Then why don't we just say n = 2a for some a. To find a, it's obvious a = n/2. We have the degree 2 term (x^2), degree 1 term (nx = 2 . n/2 .x). We need the constant of a^2. a^2 = (n/2)^2 = n^2 / 4. In this case, n = 13.
It's the same process as composite numbers. Factor them. Combine the factors, eliminating duplicates. If they have no common factors, the LCM is their product.