There is none. All the numbers have at least 1 and themselves as factors.
97
It is 97 which has only two factors because it is a prime number
In that range, 180 has the most.
Oh, what a happy little question! To find the highest common factor of 60, 75, and 100, we can first list the factors of each number. The factors of 60 are 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, and 60. The factors of 75 are 1, 3, 5, 15, 25, and 75. The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100. The highest common factor among them is 5.
The factors of 81 are 1,3,9,27,81 The factors of 100 are 1,2,4,5,10,20,25,50,100
5 x 19 = 95
To find the greatest factor of a number (other than itself) you first need to find the prime factors of that number. In this case, the prime factors of 100 are 2, 2, 5 and 5. The next step is to multiply all these together, except the smallest (2). This means you multiply 2x5x5. That works out at 50. Thus the greatest factor of 100 (other than itself) is 50.
The highest number on probability is 1 or 100%.
The highest prime number under 100 is 97.
No number under 100 has thirteen factors.
You can quickly find the factors for even numbers 50 to 100 by dividing each number by all possible factors (starting from 2) until reaching the square root of the number. If a number is divisible without a remainder, then it is a factor of that even number. Repeat this process for each even number between 50 and 100.
No, and we doubt that you can either.