The answer is 344.
370740864321110.1
23.............
419 Nachiket Joshi solution: LCM(7,6,5,4,3,2)=420 now subtract 1 frm answer ...............so the answer will be 419..... TRICK: Since the diff between the remainder and dividend is common(1 in this case ) u subtract 1 from the LCM
To find the smallest possible number that satisfies both conditions, we need to find the least common multiple (LCM) of 4 and 7, which is 28. Adding 2 to the LCM gives us the smallest number that leaves a remainder of 2 when divided by both 4 and 7. Therefore, the smallest possible number is 30.
30/21 = 1 with a remainder of 9
79.2
144
You need at least two numbers to find a GCF.
1 ÷ 3 3 ÷ 2 4 ÷ 3 5 ÷ 2 5 ÷ 4 6 ÷ 5 7 ÷ 6
The answer is indeterminate because the degree of f(x) is not specified.
The LCM is 90. It's the smallest number that can be divided exactly by BOTH numbers.
LCM of 45 & 50 = 450 so how about 456?