23.............
The number is six.
430/17=25r5 398/17=23r7
GCF(280-4, 1245-3) = GCF(276, 1242) = 138
They are factors of that number
The GCF (Greatest Common Factor) of m and n is the largest positive integer that divides both m and n without leaving a remainder.
1
The number is six.
There is no such number. 1675 - 6 = 1669 which is a prime. As a result, the only number that can divide it is 1 and 1669 itself. However, 1 not only divides 1669 but it also divides 1675. That is, 1 does not leave a remainder of 6 when dividing 1675.
966 is the smallest thats all i know
430/17=25r5 398/17=23r7
GCF(280-4, 1245-3) = GCF(276, 1242) = 138
9 is the largest integer that can divide into both 36 and 81 evenly with no remainder.
They are factors of that number
The GCF (Greatest Common Factor) of m and n is the largest positive integer that divides both m and n without leaving a remainder.
The highest common factor (HCF) of 2128 and 42 is 2, as it is the largest number that divides both 2128 and 42 without leaving a remainder.
138. What is required is the largest number n such that: 285 = jn + 9 1249 = kn + 7 So subtract the required remainders and then find the hcf of the results: 285 - 9 = 276 1249 - 7 = 1242 Find hcf of 276 and 1242: 1242 / 276 = 4 r 138 276 / 138 = 2 r 0 hcf of 276 and 1242 is 138. Thus 138 is the largest number to divide 285 with a remainder of 9 and divides 1249 with a remainder of 7.
To find the greatest number that divides 319, 572, and 1329 while leaving remainders of 4, 5, and 6 respectively, we need to use the Chinese Remainder Theorem. First, find the least common multiple of the three given divisors (4, 5, and 6), which is 60. Then, apply the Chinese Remainder Theorem to find the number that satisfies the given conditions. The solution will be the number that is congruent to 4 modulo 4, 5 modulo 5, and 6 modulo 6.