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Find the leg of each isosceles right triangle when the hypotenuse is of the given measure. Given 8 cm?
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In an isosceles right triangle the hypotenuse is radical three and if the hypotenuse is 12 then what is the smaller leg of that triangle?
If the hypotenuse is the square root of three, then the legs are (root 6)/2. If the hypotenuse is 12, then the legs are 6(root 2). This is because, for any given right isosceles triangle, the length of the hypotenuse x is root two times the length of the legs.
How do you find area of a 90 degree triangle with hypotenuse only?
The hypotenuse only is not sufficient to determine the area of a right triangle, unless the triangle is stated to be isosceles, or there is some other information that allows determination of the length of a side in addition to the hypotenuse. The area of a right triangle with a given hypotenuse only approaches zero as one of the two acute angles approaches zero degrees.
What name is given to a triangle when two of the angles equal 60?
If 2 of its interior each measure 30 degrees then it is an isosceles triangle
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
Why do you need sqrt 2 to divide the hypotenuse of a 45-45-90 triangle?
A 45-45-90 triangle is an isosceles right angled triangle. If its two short sides are of length x units then, by Pythagoras, the hypotenuse is given by: hypotenuse2 = x2 + x2 = 2x2 Taking square roots, hypotenuse = sqrt(2x2) = sqrt(2)*x
In an isosceles right triangle the hypotenuse is radical three and if the hypotenuse is 12 then what is the smaller leg of that triangle?
If the hypotenuse is the square root of three, then the legs are (root 6)/2. If the hypotenuse is 12, then the legs are 6(root 2). This is because, for any given right isosceles triangle, the length of the hypotenuse x is root two times the length of the legs.
Find the leg of each isosceles right triangle when the hypotenuse is of the given measure given equals 6 square root 2?
Since the hypotenuse equals the leg times the square root of 2, the answer is the number in front of the square root...in your case, 6.
How do you find area of a 90 degree triangle with hypotenuse only?
The hypotenuse only is not sufficient to determine the area of a right triangle, unless the triangle is stated to be isosceles, or there is some other information that allows determination of the length of a side in addition to the hypotenuse. The area of a right triangle with a given hypotenuse only approaches zero as one of the two acute angles approaches zero degrees.
What name is given to a triangle when two of the angles equal 60?
If 2 of its interior each measure 30 degrees then it is an isosceles triangle
What is The sum of any 2 sides of an isosceles triangle?
Depends from the given information. For example, if it is given the measure of the angle base θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/cos θ If it is given the measure of the angle base θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/sin θ If it is given the measure of the vertex angle θ, and the length of the base b, the sum of the sides a of the isosceles triangle equals to 2a = b/sin θ/2 If it is given the measure of the vertex angle θ, and the length of the height h, the sum of the sides a of the isosceles triangle equals to 2a = 2h/cos θ/2 If it is given the length measures of the base b and the height h, the sum of the sides a of the isosceles triangle equals to 2a = √(h4 + b2) (from the Pythagorean theorem)
Given the legs a and b of a triangle are 3 and 4 then the hypotenuse is?
Given the legs a and b of a triangle are 3 and 4, the hypotenuse is: 5
Why do you need sqrt 2 to divide the hypotenuse of a 45-45-90 triangle?
A 45-45-90 triangle is an isosceles right angled triangle. If its two short sides are of length x units then, by Pythagoras, the hypotenuse is given by: hypotenuse2 = x2 + x2 = 2x2 Taking square roots, hypotenuse = sqrt(2x2) = sqrt(2)*x
What is the measure of each angle of an isosceles triangle?
We have no way to know that, from the information given in the question. All we know, if the triangle is isosceles, is that two of the angles are equal, and that all three angles sum to 180 degrees.
How to solve for the base of isosceles triangle when only two sides are given?
You will also need the angles so that you can use the Isosceles Triangle Theorems to solve for the base of isosceles triangle when only two sides are given.
How do you determine what side of the triangle is the hypotenuse?
Given a right triangle, the hypotenuse is the longest side or simply the side opposite the 90o angle.
How do you find the height of an isosceles triangle when given only the three side lengths?
Make it a right triangle where one side of the right triangle is half the length of the non-identical side of the isosceles, the hypotenuse of the right triangle is the length of one of the identical sides of the isosceles triangle, then use the Pythagorean theorem. a^2+b^2=c^2. Where "a" is the length of one of the identical sides, and "c" is the length of half the non-identical sides. Solve for "b" and that is your height.
Is it possible to find the dimensions and area of a right angle triangle when given only its hypotenuse which is 8 cm?
No.Additional Information:-Yes providing it's not an isosceles right angle triangle the possible dimensions are:- hypotenuse 8 cm, height 6.4 cm and base 4.8 cm because they comply with Pythagoras' theorem.So the area is:- 1/2*6.4*4.8 = 15.36 square cmNote that if it was an isosceles triangle then the dimensions and area could also be worked out that is why you should have specified in your question the type of triangle.
