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OK so we have two formulas:

Length = width + 5 (since legth is 5 more than width)

length + width + length + width = perimeter= 82 (form. for perm.)

so we can replace every instance of "length" with "width + 5" since they are the same.

width + 5 + width + width + 5 + width = 82

4xwidth + 10 = 82

4X width = 72

width = 23

so now go back and replace "width" with 23.

length = 23 + 5

length = 28

There you go.

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โˆ™ 2009-10-23 05:12:31
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Q: Find the length of a rectangular lot with a perimeter of 82m if the length is 5 m more than the width?
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