Q: How do you find the width of a rectangle if you know the perimeter and the length?

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you need length and width length multiply width = area length + length + width + width = perimeter

Length + length + width + width = perimeter. Length + width x 2 = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

You divide the perimeter by the width and you get the lenght

length 18 width 7

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you need length and width length multiply width = area length + length + width + width = perimeter

perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in

Length + length + width + width = perimeter. Length + width x 2 = perimeter

You divide the perimeter by the width and you get the lenght

Length = (Perimeter - twice width) / 2

by appying 2l+2w

length 18 width 7

Perimeter = 2*(L + W).

a rectangle has a perimeter of 72m. If the length is 20 m longer than the width find its dimensions?