0
What else can I help you with?
Find the determinant of 1 a AA AA 1 a a AA 1?
Assuming that the terms, a and AA, are commutative, It is 1 + a^3 + (AA)^3 - 3aAA
How do you find the variable in this matrix 3 -2 5 a ...the determinant is 7?
If it a 2x2 matrix, the determinant is 3*a - (-2)*5 = 3a + 10 = 7 So 3a = -3 so a = -1
What is the determinant of matrix image?
1
What is the determinant of an idempotent matrix?
0 or 1
How do you find the area of a triangle using matrix methods?
Put the three points in a matrix with the last column with ones. Then find the determinant, then multiple by .5 Example: (1,1) (2,4)(4,2) 1 1 1 2 4 1 4 2 1 The determinant is: [(1*4*1)+(1*1*4)+(2*2*1)]-[(1*4*4)+(1*2*1)+(1*2*1)]=12-20= -8 Therefore you must multiple by -.5= 4
What is the solution of this question By wronskian determinant method please find whether the solution exist or not where.... y and 8321cos and sup2x y and 83221 plus cos2x?
What is the solution of this question By wronskian determinant method please find whether the solution exist or not where.... y1 = (squre of) cos x, y2 = 1 + cos 2 x.
What does rank 1 rank 2 rank 3 rank 4 rank 5 rank 6 rank 7 rank 8 rank 9 and rank 10 mean on www.xfire.com?
1, 1, 3, 6, 6, 6, 9
What is the possible determinant of unitary matrix?
|Det(U)| = 1 so that Det(U) = ±1
How do you find your rank in Mario Kart?
1. Go to Mario Kart Chanel and click on 'Rankings'
What is the rank of acropolis in mp?
1 rank ..
What is the rank of mtu in up?
1 rank
Matlab code for finding determinant and inverse of a matrix without using in built function?
To find the determinant of a matrix in MATLAB without using built-in functions, you can implement a recursive function that utilizes cofactor expansion. For the inverse, you can use the adjugate method, which involves calculating the matrix of minors, cofactors, and then transposing it before dividing by the determinant. Here’s a simple illustration: function detA = myDet(A) n = size(A,1); if n == 1 detA = A(1,1); elseif n == 2 detA = A(1,1)*A(2,2) - A(1,2)*A(2,1); else detA = 0; for j = 1:n detA = detA + ((-1)^(1+j)) * A(1,j) * myDet(A(2:end,[1:j-1,j+1:end])); end end end function invA = myInverse(A) detA = myDet(A); if detA == 0 error('Matrix is singular, cannot compute inverse'); end adjA = zeros(size(A)); for i = 1:size(A,1) for j = 1:size(A,2) minor = A; minor(i,:) = []; minor(:,j) = []; adjA(j,i) = ((-1)^(i+j)) * myDet(minor); % Cofactor end end invA = adjA / detA; % Divide by determinant end Make sure to call myInverse(A) to get the inverse and myDet(A) for the determinant of matrix A.
