Put the three points in a matrix with the last column with ones. Then find the determinant, then multiple by .5
Example:
(1,1) (2,4)(4,2)
1 1 1
2 4 1
4 2 1
The determinant is: [(1*4*1)+(1*1*4)+(2*2*1)]-[(1*4*4)+(1*2*1)+(1*2*1)]=12-20=
-8
Therefore you must multiple by -.5= 4
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how to find the perimeter of a right angled triangle using the area
The area of a right triangle that has legs 7 cm and 4 cm long can be calculated using the fact that a right triangle is half of a rectangle. The area of a rectangle is l*h, so the area of a right triangle is l*h/2. In this case, the area is 14 cm^2.
The area of triangle is : 24.0
The area of a triangle can be calculated with one main formula. That is, A=(b*h)/2, where A is the area of the triangle, b is the base of the triangle, and h is the height of the triangle.
The solution depends on the information supplied. Basically, you find the area of the sector containing the segment and then deduct the area of the triangle formed by the chord and the two radii enclosing the sector. If you are given the radius(r) of the circle and the height(h) then construct a radius that is perpendicular to and bisects the chord. This will create two congruent triangles which together form the main triangle. Using Pythagoras enables the half-chord length to be calculated as the hypotenuse is r and the height (also the length of the third side) is r-h. With this information the full chord length can be established and thus the area of the main triangle. Using sine or cosine methods enables the sector angle at the centre to be calculated and thus the sector area. Simple subtraction produces the area of the segment. If you are given the radius and the chord(c) length then the construction referred to above enables the height of the main triangle to be calculated and a similar process will generate the area of that triangle and the sector area. This, in turn, will enable the segment area to be determined.