f(x) = -x2 + 6x - 4
∴ f'(x) = -2x + 6
Solve for f'(x) = 0:
0 = -2x + 6
x = 3
So the peak occurs at the point where x = 3. Now you can calculate the value of f(3)
f(3) = -32 + 6(3) - 4
∴ f(3) = -9 + 18 - 4
∴ f(3) = 5
So the maximum value of that function is 5, and it occurs when x = 3.
To prove that it's a maximum, take the second derivative:
f'(x) = -2x + 6
∴ f''(x) = -2
Because it's negative, we know that this is the peak of the curve.
The answer is 27 (6x4=24, 24+3=27)
3 - 2 + 6 x 4 = 25
A = 4 (7x4) + 8 = 36 (6x4) + 14 = 36
6x4=24
It has two complex roots.
6X4=24
- 3X3 + X2 + 17 + 6X4 - 3 = coefficient of the variable term X3 6 = coefficient of the variable term X4 ----------------------------------------------------------- I do not know how you are being taught, but...... 1 = the implied coefficient of the variable term X2 S0 I would say three coefficients, but your teacher may say two. Consult your text on the implied coefficient 1.
1500 to 2000 US cents will fit into a 6x4 jar.
The answer is 24. How that works you find 8x3 and 6x4 anything below it would not work
24
The answer is 24
24