It has two complex roots.
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No.The roots are the complex conjugate pair 5 ± 2.4495iwhere i is the imaginary square root of -1.
3x^2 + 8x + 4 = (x+2) (3x+2) x = -2 x = -2/3 So there are no complex roots, they are real. You can test this by b^2 - 4ac if greater than 0, it is real if equal, there will be 2 identical roots. if less than 0 you get imaginary roots.
It is a quadratic equation with one unknown variable, x which has no real roots.
No answer in integers. Quadratic formula gives roots of x2 + x - 26 = 0 as 5.625 and -4.625
The discriminant formula. b2 - 4ac 32 - 4(1)(8) 9 - 32 = - 23 ===========This shows no real roots to this function.