Best Answer

Sum(not div by 7) = Sum(all) - Sum(div by 7)

Now the sum of an AP is

Sn = n/2 (first + last)

where n is the number of terms

Sum(All) = 10000/2 (1 + 10000) = 50005000

Sum(div by 7) = (9996/7)/2 (7 + 9996) = 1428/2 (10003) = 7142142

Sum(not div by 7) = Sum(all) - Sum(div by 7)

= 50005000 - 7142142

= 42 862 858

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Q: Find the sum of all positive integers not greater than 10000 that are not divisible by 7?

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It is 83667.

10000 = 16 x 625

625*16=10000625+16=641

Counting 10000, there are 17999.

One less than 10000.

This is easiest to answer by summing all the numbers 1-10000 and subtracting the sum of the multiples of 7 (7, 14, 21, ..., 9996). The sum of a series is: S = (first + last) x number_of_terms / 2 For for 1-10000, the sum is: S1 = (1 + 10000) x 10000 / 2 = 10001 x 5000 = 50005000 For the multiples of 7 the sum is: S2 = (7 + 9996) x 1428 / 2 = 10003 x 714 = 7142142 So the sum of all integers not greater than 10000 that are not divisible by 7 is: S = S1 - S2 = 50005000 - 7142142 = 42,862,858

No. If a number is divisible by three, the sum of its digits will be divisible by three. Obviously, the sum of the digits of 10000 is 1, and 1 is not divisible by 3, so 10000 is not divisible by 3.

10000/3 is 3333.3recurring, so no, it is not divisible by 3

9000 integers.

125

Let me first re-phrase your question: What is the number of (positive) integers less than 10000 (5 digits) and greater than 999 (3 digits)? The greatest 4 digit integer would be 9999. The greatest 3 digit integer would be 999. Let's do some subtraction: 9999 - 999 = 9000 This works because as we count up from 999, each positive integer encountered satisfies your requirements until reaching 10000.

w

No. 10,000 is not evenly divisible by 32.

10,000 is composite. It is divisible by 2.

Int(10000/3) = Int(3333.3) = 3333

270421/10000 = 27.0421

298469 + 10000 = 308469

30,000

the trick to this is to realize the pattern: 10000=0+10000 10000=1+9999 10000=2+9998 ... 10000=4999+5001 so there are 5000 (10000s) and the unmatched 5000 in the middle = 50,005,000

There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.

The square numbers integers between 576 and 10000 (and their square roots, in the left column) are: 245762562526676277292878429841309003196132102433108934115635122536129637136938144439152140160041168142176443184944193645202546211647220948230449240150250051260152270453280954291655302556313657324958336459348160360061372162384463396964409665422566435667448968462469476170490071504172518473532974547675562576577677592978608479624180640081656182672483688984705685722586739687756988774489792190810091828192846493864994883695902596921697940998960499980110010000

There are 20 palindromes between 10,000 and 99,999 that are divisible by 25.

idhytugh

Factors of 15 are 1, 3, 5 and 15. Starting with the greatest number, 15 is not divisible by 130. Then, 5 is both divisible by 130 and 10000. So the answer is 5.

Because it can be expressed as the ratio of two integers. 10227/10000