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Let me first re-phrase your question: What is the number of (positive) integers less than 10000 (5 digits) and greater than 999 (3 digits)?
The greatest 4 digit integer would be 9999.
The greatest 3 digit integer would be 999.
Let's do some subtraction: 9999 - 999 = 9000
This works because as we count up from 999, each positive integer encountered satisfies your requirements until reaching 10000.
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What is the lowest 4 digit numbers?
The lowest positive 4-digit number is 1000
How many 2-digit positive integers are there such that product of their two digit is 24?
-22
How many four digit positive integers are there with thousands digit 2?
There are one thousand. Starting at 2000 and going to 2999
How many odd 2-digit positive integers less than 50 are there?
-48
How many four digit whole numbers are there such that the thousand digit is odd the hundreds digit is even and all four digits are different?
5*5*4*4 = 400
What is the smallest positive 4 digit multiple of 17?
The smallest, positive 4-digit multiple of 17 is 1,003.
What is the lowest 4 digit numbers?
The lowest positive 4-digit number is 1000
How many 3 digit positive numbers are there without 2 4 and 6?
There are 294 such numbers.
How may two digit-numbers contain the digit 4?
18 positive integers and 36 integers (negative and positive)
How many 4-digit positive even numbers are there?
4,000 even numbers, 4,000 odd numbers.
How many 2-digit positive integers are there such that product of their two digit is 24?
-22
How many two-digit positive integers are there?
90
How many positive three-digit perfect cubes are even?
I believe there are 2 positive three-digit perfect cube numbers, that are even.
What is the sum of largest 4-digit positive integer and smallest 3-digit negative integer?
1
How many 3 digit positive integers are odd and do not contain the digit 5?
-2
How many positive four digit integers have 1 as their first digit and 2 or 5 as their last digit?
There are 200 positive four digit integers that have 1 as their first digit and 2 or 5 as their last digit. There are 9000 positive four digit numbers, 1000 through 9999. 1000 of them have 1 as the first digit, 1000 through 1999. 200 of them have 2 or 5 as their last digit, 1002, 1005, 1012, 1015, ... 1992, and 1995.
How many 5 digit palindromes are there?
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
