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Sum of 1st 2 terms, A2 = 2 + 4 = 6

Sum of 1st 3 terms, A3 = 2 + 4 + 6 = 12

Sum of 1st 4 terms A4 = 2 + 4 + 6 + 12 = 20

you can create a formula for the sum of the 1st n terms of this sequence

Sum of 1st n terms of this sequence = n2 + n

so the sum of the first 48 terms of the sequence is 482 + 48 = 2352

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โˆ™ 2010-06-07 22:47:51
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Q: Find the sum of the first 48 terms of an aritmetic sequance 2 4 6 8?
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