To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
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you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
Find the sum of the first 11 terms in the sequence 3 7 11
-69
To find the sum of the first 20 terms of an arithmetic progression (AP), we need to first determine the common difference (d) between the terms. Given that the 6th term is 35 and the 13th term is 70, we can calculate d by subtracting the 6th term from the 13th term and dividing by the number of terms between them: (70 - 35) / (13 - 6) = 5. The formula to find the sum of the first n terms of an AP is Sn = n/2 [2a + (n-1)d], where a is the first term. Plugging in the values for a (the 1st term), d (common difference), and n (20 terms), we can calculate the sum of the first 20 terms.
because you add the first 2 terms and the next tern was the the sum of the first 2 terms.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
The Nth partial sum is the sum of the first n terms in an infinite series.
well the first four terms are n=1,2,3 and 4 so just substitute those numbers into k=3n so k= 3,6,9,12
i need it nowww
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given
Find the sum of the first 11 terms in the sequence 3 7 11
It seems that you can't express that integral in terms of a finite number of commonly used functions. In the Wolfram Alpha site (input: "integral cos sin x"), you can find the first few terms of an infinite series expansion.
2
2n+4: 6,8,10......104........204