It seems that you can't express that integral in terms of a finite number of commonly used functions. In the Wolfram Alpha site (input: "integral cos sin x"), you can find the first few terms of an infinite series expansion.
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f(x)=sinx+cosx take the derivative f'(x)=cosx-sinx critical number when x=pi/4
2
(1-cosx)/sinx + sinx/(1- cosx) = [(1 - cosx)*(1 - cosx) + sinx*sinx]/[sinx*(1-cosx)] = [1 - 2cosx + cos2x + sin2x]/[sinx*(1-cosx)] = [2 - 2cosx]/[sinx*(1-cosx)] = [2*(1-cosx)]/[sinx*(1-cosx)] = 2/sinx = 2cosecx
sinx cscx = 1 is the same thing as sinx(1/sinx) = 1 which is the same as sinx/sinx = 1. This evaluates to 1=1, which is true.