Try 8 m/s^2
After one second, it would have increased velocity by 8 ms, making it 40 ms
After two seconds, it would be 48 ms
After 3, 56
4, 64
5, 72
6, 80
7, 88
8, 96
Calculation to find this- 96-32= 64, which will be evenly divided by 8 if it is a uniform acceleration, so 64/8= 8, accelerations units are meters per second squared, so
8 m/s^2
Constant velocity is a measure of distance traveled per unit of time at a uniform speed, such as miles per hour or feet per second. Constant acceleration is a measure of a continuing increase in velocity per unit of time, as when a car speeds up from 30 miles per hour to 40 miles per hour in 5 seconds, then from 40 miles per hour to 50 miles per hour during the next 5 seconds. It will then have had a constant acceleration of 10 miles per hour per 5 seconds.
if under uniform acceleration or deceleration v = u + (a*t) where: v = instantaneous velocity u = initial velocity a = acceleration (negative if decelerating) t = time elapsed
V = constant Speed = constant Direction = constant Acceleration = 0
If body is moving in a circle with uniform or constant speed its acceleration will be uniform as velocity i.e. to say direction is changing at every point.
The formula for distance covered during uniform acceleration isd = 1/2 * (vf + vi) * t (1)Time, t, is given; initial velocity, vi, is 0; but final velocity, vf, is unknown and must be computed from given information. Knowing the rate of acceleration, initial velocity and time, The final velocity may be computed using the formula for average acceleration (actual acceleration under uniform motion) which isa = (vf - vi) / t (2)Rewriting to solve for vf with vi = 0 we havevf = a * tvf = 6m/s2 * 12svf = 72m/sPlugging this value into equation (1) with the other given values we haved = 1/2 * (72m/s + 0 m/s) * 12sd = 432mSo the airplane will travel 432m from rest in 12 seconds under 6m/s uniform acceleration.
No, uniform angular velocity means no angular acceleration.
Although the question is stated in a somewhat confusing way, we can state withconfidence that the velocity of the car is NOT uniform, because a value is given forits acceleration. 'Uniform' motion means zero acceleration.
Uniform velocity is velocity unaffected by acceleration. Variable velocity is velocity affected by acceleration. Lauren "Physics above all!"
Uniform velocity means the velocity is not changing. Acceleration is defined as the rate of change of velocity. If velocity isn't changing, the rate of change is zero.
Find out the time using speed and acceleration, (time=speed/acceleration) and then use it to find out uniform velocity. From that find out uniform acceleration. (as uniform acceleration is equal changes of velocity over equal intervals of time)
The slope of a velocity-time graph that shows uniform acceleration is the actual acceleration. Instantaneous velocity is the velocity of a body at a particular moment in time.
Acceleration is change of velocity divided by time; so if the velocity doesn't change, acceleration is zero.
The body is not zero, but the sum of all forces on it is. -- "Uniform velocity" means no acceleration. -- Acceleration is force/mass . -- If acceleration is zero, that's an indication that force must be zero.
It has zero acceleration!!
"Uniform velocity" means zero acceleration, that is, constant speed in a straight line.rate of change of velocity is zero
"Uniform motion" means constant velocity ... constant speed in a straight line. "Acceleration" means any change in velocity ... speed or direction. So 'uniform motion' means zero acceleration.
A positive acceleration is a change in velocity such that the latter velocity is greater than the former velocity and is therefore going fasterwhile a negative acceleration or deceleration is a change in velocity such that the latter velocity is lesser than the former velocity and is therefore going slower.Now let us look at the equation of a uniform acceleration (the change in velocity is uniform):a = (vf-vi)/sIf the final velocity is greater, you will have a positive acceleration. If the initial velocity is greater, you will have a deceleration.