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Given the linear equation 3x - 2y^6 = 0, the x and y intercepts are found by replacing the x and y with 0. This gives the intercepts of x and y where both = 0.
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How do you find the x and y intercepts of an equation?
Substitute zero for x to find the y-intercept, and substitute zero for y to find the x-intercept.
Find intercepts of xy equals 4?
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
What does factoring a quadratic allow you to do?
Factoring a quadratic allows you to solve the x and y intercepts. The x-intercepts in the factored form are the inverse of the constants. The y-intercept is the product of the x-intercepts multipied together. Example: x²-10x-24 = (x+2)(x-12) +2 and -12 are the constants. So ur x-intercepts are (-2,0) (12,0). The y intercept is -24 because -2 X 12 = -24.
How do you find x intercepts in a quadratic function?
The quadratic (parabola) intercepts the x-axis when y = 0. So substitute y=0 into y = f(x). Then you can solve for the x-values by any number of ways: Factoring, completing the square, or Quadratic Formula. It may turn out that the values of x which satisfies y=0 are complex {have an imaginary component}, which will tell you that the parabola does not have an x-intercept.
What are the intercepts of 2x-3y-4z equals -24?
2x-3y-4z=-24 has 3 potential intercepts. The x, y and z interceps. To find the x intercept we set y=z=0 This gives 2x=-24 or x=-12 To find the z intercept we set x=y=0 This gives -4z=-24 or z=6 Lastly to find the y intercept, x=z=0 so -3y=-24 and y=8 The x intercept is (-12,0,0), the y intercept is (0,8,0) and the z intercept is (0,0,6)
What if you cant do find the x intercepts?
Then there is no x-intercept. No big deal. Lots of functions do not have x- intercepts. For example, y = x2 + 1 or y = 2x
How d yu find x and y intercept on a graph?
In the equation y = f(x), Put x = 0 and solve for y. Those are the y intercepts. Put y = 0 and solve for x. Those are the x intercepts.
How do you find the x and y intercepts of an equation?
Substitute zero for x to find the y-intercept, and substitute zero for y to find the x-intercept.
What is the x coordinate for all y-intercepts?
The x coordinate for all y intercepts is 0, just as the y coordinate for all x intercepts is 0.
How do you find the numbers x-intercepts of function y equals 5x'2?
5x²=0 X=0 the function y=5x² only intercepts x when x = 0
How to find the x-intercepts when there is no y?
If there is no y, then the equation is of the form x = c where c is some constant value. And so the line intercepts the x axis at (c,0).
What are x and y intercepts?
The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.
Find the x and y intercept of 9x54-6y?
I believe that you need an equation to solve for the x and y intercepts.
How do you find the x and y intersepts?
plug in 0 to x and y values P.S. you spelt Intercepts wrong
Find intercepts of xy equals 4?
There are no intercepts because the curve, xy = 4 is asymptotic. When x = 0 (where the y intercept would be) y is infinite, and conversely, when y = 0 x is infinite.
How do you find the maximum height of a parabolic path?
If "a" is negative then the graph is a cap. Find the x intercepts. Average the two x intercepts and substitute that into the equation it will give you the y.
How do you find the intercepts to the equation x2 plus y-49 equals 0?
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49General Solutionset x=0 to find your y-intercept and set y=0 to find your x-intercept. That's how you will always find your intercepts, no matter what the equation is.Ex. So if you find that when x=0, y=a, then the y-intercept is at the point (0,a).Similarly, if you find that when y=0, x=b, then the x-intercept is at the point (b,0).You can solve any problem from here.
